f(x)在x0处有定义是f(x)在x0处连续的()

求limx→∞x{√[1+sin(1/x)-1]}

设f(x) {ex-2,x≥0, e1/x-1,x＜0, 求limx→0f(x)

计算：limx→-1[1/(x+1)-3/(x3+1)]

求limx→0[(ex+e-x-2)/3x]

求极限limx→0(1+3x)1/2x

x=0是f(x)=arctan(1/x)的()

limx→∞(1-e1/n)sinn=()

limn→∞(2n2+3n-2)/(n2+1)=()

极限limx→∞xsin(1/x)=()